A twin-engine plane flies 380 mi in the same amount of time it takes a single-engine plane to fly 220 mi. The rate of the twin-engine plane is 80 mph faster than the rate of the single-engine plane. Find the rate of the single-engine plane.

Answer: The rate of the single engine plane is 110 mph. Step-by-step explanation:Let the rate of single engine plane be n mph,And the rate of twin engine plane will be n + 80 mph. We know that, distance = speed x time. Then, for twin engine plane 380 = (n + 80) x time taken [tex]\text{{time taken}} = \frac{380}{n+80}[/tex]And, for single engine plane 220 = n x time taken [tex]\text{{time taken}} = \frac{220}{n}[/tex] It is given that, both planes took same time. Then, [tex]\frac{380}{n +80} = \frac{220}{n}[/tex] 380n = 220n + 220 x 80   380n – 220n = 17600   160n = 17600[tex]n =\frac{17600}{160}[/tex]   n = 110 Hence, the rate of the single engine plane is 110 mph.